Question

2 blocks of masses 2 kg and 1 kg are in contact with each other on A frictionless table when a horizontal force of three N is applied to thw block of mass 2 kg the value of force of contact between two blocks is?

Answer 1

Since, the two blocks will move together, their acceleration will also be same.

Let the acceleration of the two blocks be 3 kg

Now, Total mass = 2 + 1 = 3 kg

Force applied = 3 N

F = ma

$a = \frac{F}{m}$

$a = \frac{3}{3}$

a = 1 m/s^2

Let the force between the two blocks be: $F_c$

Now, F(net) equation for block of 2 kg

$3 - F_c = m_2 \times a$

$F_c = 3 - 2 \times 1$

$F_c = 1$ N

Hence, the force of contact between the two blocks is 1 N