Question

2 bodies of masses 2kg and 4kg are moving towards each other along a horizontal frictionless surface with velocities 20m/s and 40/s respectively .if they collide and stick together find the final velocity

Answer 1

HEY DEAR,

HERE IS YOUR ANSWER.......

AS WE KNOW,

IN THIS CASE MOMENTUM REMAINS CONSERVED...

LET,

 MV + mv = (M + m) V.   .......................... (1.)

PUT VALUES IN THIS EQUATION ..

(2*20) + ( 4* 40) = (2+4)V

40 + 160  = 6V

V= 33.33 m(sec^-1)

so, required velocity is 33.33 metre per second..

HOPE IT HELPS YOU....

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THANKS    ..    :)

Answer 2

Your answer is :-


m1 = 2kg and m2 = 4kg

u1 = 20m/s and u2 = 40m/s

°•° net force on whole system is zero

So,we apply momentum conservative

•°• according to conservative of moment

m1u1+m2u2 = (m1+m2)v

=> 2×20+4×40 =(2+4)v

=> 40+160 = 6v

=> 200 = 6v

=> v = 200/6

=> v = 33.33m/s

hence,final velocity is 33.33m/s after collision