Physics, asked by sdsdsd, 1 year ago

2 bodies of masses 2kg and 4kg are moving towards each other along a horizontal frictionless surface with velocities 20m/s and 40/s respectively .if they collide and stick together find the final velocity

Answers

Answered by DreamGirl01
36

HEY DEAR,

HERE IS YOUR ANSWER.......

AS WE KNOW,

IN THIS CASE MOMENTUM REMAINS CONSERVED...

LET,

 MV + mv = (M + m) V.   .......................... (1.)

PUT VALUES IN THIS EQUATION ..

(2*20) + ( 4* 40) = (2+4)V

40 + 160  = 6V

V= 33.33 m(sec^-1)

so, required velocity is 33.33 metre per second..

HOPE IT HELPS YOU....

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THANKS    ..    :)


sdsdsd: Okkk
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Answered by Anonymous
43
Your answer is :-


m1 = 2kg and m2 = 4kg

u1 = 20m/s and u2 = 40m/s

°•° net force on whole system is zero

So,we apply momentum conservative

•°• according to conservative of moment

m1u1+m2u2 = (m1+m2)v

=> 2×20+4×40 =(2+4)v

=> 40+160 = 6v

=> 200 = 6v

=> v = 200/6

=> v = 33.33m/s

hence,final velocity is 33.33m/s after collision

Anonymous: thanks
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