Question

2 bodies of masses m1 and m2 are acted upon by a constant force F for a time t They start from rest and acquire kinetic energies E1 and E2 then E1/E2 is

Answer 1

Doesn’t seem like it has enough information.

E = (1/2)mv2

(1/2)m1v21

= (1/2)m2v22

m1v21

= m2v22

p1v1

= p2v2

(p1)/(p2)

= (v2)/(v1)

So the two objects’ momenta ratio would be (v2)/(v1)

.

Answer 2

⭐《ANSWER》

↪Actually welcome to the concept of the Chemical KINEMATICS OF A BODY

↪So basically we get as

〽since KINETIC ENERGY = P^2/2m

↪P = momentum

↪So here using the formula we get as


↪ E1/E2 = P^2/2m1 ÷ P^2/2m2