Question

2 boys are on opposite sides of a tower of 100 mts height. They measure the angle of elevation of the top of the tower as 30degrees and 40 degrees respectively. The distance which the boys are seperated is.
(a) 100/root 3 mt, 100 mts
(b) 100* root 3 mts, 100mts
(c) 100mts, 100/root 3 mts
(d) none of these​

Answer 1

Answer:

Distance between them is

Distance between them is=(100/tan45°)+(100/tan30°)

Distance between them is=(100/tan45°)+(100/tan30°)=(100/1)+(100*_/3)

Distance between them is=(100/tan45°)+(100/tan30°)=(100/1)+(100*_/3)=100+173.2

Distance between them is=(100/tan45°)+(100/tan30°)=(100/1)+(100*_/3)=100+173.2=273.2m(almost)