Question

2-Bromo-2-methylpropane is allowed to react with alcoholic KOH solution. The major product formed is
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Answer 1

Answer:

2-Bromo-3-methyl butane on treatment with alcoholic KOH forms 2-Methyl-2-butene. The product formed is in accordance with which rule: Huckel's rule.

Explanation:

Pent-2-ene is major product known as Saytzeff's Product and it is more stable alkene.

The process is known as β− elimination as it involves elimination of β− Hydrogen.