Question

2-Bromopentane is heated with potassium ethoxide in ethanol. The major product obtained is
1) 2-Ethoxypentane
2) pent-1-ene
3) cis-pent-2-ene
4)trans-pent-2-ene


Plz anwer this question with suitable solution and explanation​

Answer 1

Your answer is trans pent - 2 ene. Because, Potassium ethoxide in alcohol acts as a strong base, and eliminates the hydrogen atoms. In stability, pent-2-ene is more stable than pent-1-ene. And among cis and trans isomers, ttrans isomers are more stable

The reaction is given in the attachment

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