2 buildings are situated 200m apart. With what speed must ball be thrown horizontally from the window 540 m above the ground in one building, so that it will enter a window 50 metre above the ground in the other?
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this question is based on concept of horizontal projectile .
use trajectory equation of Horizontal projectile.
e.g Y = gx²/2u²
where Y is the displacement of object in y-component wrt to frame , x is the displacement of object in x -component wrt frame . g is acceleration due to gravity and u is intial velocity.
here ,
Y = 200 m
x = 540 -50 = 490 m
now,
200 = 10 (490)²/2u²
40 = (490)²/u²
u² = (490)²/40
u = 490/2√10
=77.47 m/s
use trajectory equation of Horizontal projectile.
e.g Y = gx²/2u²
where Y is the displacement of object in y-component wrt to frame , x is the displacement of object in x -component wrt frame . g is acceleration due to gravity and u is intial velocity.
here ,
Y = 200 m
x = 540 -50 = 490 m
now,
200 = 10 (490)²/2u²
40 = (490)²/u²
u² = (490)²/40
u = 490/2√10
=77.47 m/s
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