Question

2 bulbs are connected in parallel across a 220v supply draw 10a current. If power in one bulb is 400w then resistance of second is

Answer 1

Current of 2 bulbs = 10A
V = 220 V
P1 = 400W
P1 = V x I1
400 = 220 x I1
I1 = 1.81A
Therefore, I = I1 + I2
10 = 1.81 + I2
I2 = 8.19A
P2 = V x I2
P2 = 220 x 8.19
P2 = 1801.8A
P2 = 1.8kW

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