2 bulbs of rate 10w120v and 100 w 120v are connected in series. All are connected to 120v . Find the current through each bulb. Masters please answer. Don't copy from net. Plzz dove it.. it's urgent. Don't spam
Answers
Answer:
Answer:= 0.075 A
Answer:= 0.075 AExplanation:
Answer:= 0.075 AExplanation:Resistance R1 = v²/p=120²/10=1440 ohm
Answer:= 0.075 AExplanation:Resistance R1 = v²/p=120²/10=1440 ohm R2= 120²/100=144 ohm
Answer:= 0.075 AExplanation:Resistance R1 = v²/p=120²/10=1440 ohm R2= 120²/100=144 ohm Resistor (bulb) connected into series, so
Answer:= 0.075 AExplanation:Resistance R1 = v²/p=120²/10=1440 ohm R2= 120²/100=144 ohm Resistor (bulb) connected into series, so R1+R2 = 1440+144=1584 ohm
Answer:= 0.075 AExplanation:Resistance R1 = v²/p=120²/10=1440 ohm R2= 120²/100=144 ohm Resistor (bulb) connected into series, so R1+R2 = 1440+144=1584 ohm Current = V/R1+R2 = 120/1584 = 0.075 A
Answer:= 0.075 AExplanation:Resistance R1 = v²/p=120²/10=1440 ohm R2= 120²/100=144 ohm Resistor (bulb) connected into series, so R1+R2 = 1440+144=1584 ohm Current = V/R1+R2 = 120/1584 = 0.075 A current are not distribute into series connection, therefore current through each bulb is 0.075 A.
Answer:
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