Question

2 bulbs rating 10 w ,2 fans of rating 60 w and one refrigerator of 1.8 kw are used 10 hrs daily. find total electrical energy consumed in april 2020​

Answer 1

Answer:

Each bulb rating = 10w

Each Fan rating = 60w

Refrigerator rating= 1.8kw

2 bulbs = 2×10=20w

2 fans = 2×60=120w

total power =

= 20w+120w+1.8kw

=140w+1.8kw

= 140/1000+1.8kw

=0.14kw+1.8kw

=1.94kw

time consumption in a month

=10×30

=300hrs

total energy consumed=

time taken×total power

=300×1.94

=300/100×194

=3×194

=582kwh