Math, asked by satishkumarsingh9450, 3 months ago

2 bus moving at the speed of 75km/h and 57km/h leave from the same place to the same destination. Find distance between them after 3h and 25min .​

Answers

Answered by swapnaranisahu115
0

Answer:

d1-75*3*5/12=93.75

d2-57*3*5/12=71.25

distance between them is 93.75km-71.25km=22.5

Answered by VineetaGara
0

Given,

2 buses are moving at the speed of 75 Km/h and 57 Km/h.

Both buses leave from the same place to the same destination.

To find,

The distance between them after 3h and 25min.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

speed (s) = distance traveled (d)/time of journey(t)

=> Distance traveled (d) = speed (s) x time of journey(t)

{Statement-1}

According to the question;

The total distance covered by the first bus in 3h and 25min

= speed (s) x time of journey(t)

= 75 Km/h × (3h and 25min)

= 75 Km/h × {3h + (25/60)} hrs

{ Since 1 hr = 60 mins => 1 min = 1/60 hrs}

= 75 Km/h × {3h + 0.416} hrs

= 75 Km/h × 3.416 hrs

= 256.25 Km

And, the total distance covered by the second bus in 3h and 25min

= speed (s) x time of journey(t)

= 57 Km/h × 3.416 hrs

= 194.75 Km

So, the distance between them after 3h and 25min

= (total distance covered by the first bus) - (total distance covered by the second bus)

= 256.25 Km - 194.75 Km

= 61.5 Km

Hence, the distance between the two buses is 61.5 Km.

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