2 by 3 y +1=5 by 3(y+1by 4)
verify LHS =RHS
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Solve each of the following equations. Also, verify the result in each case.
3x − 2 (2x − 5) = 2(x + 3) − 8
3x − 2 (2x − 5) = 2(x + 3) − 8
On expanding the brackets on both sides, we get
=> 3x−2×2x+2×5 = 2×x + 2×3 −8
=> 3x −4x + 10 = 2x + 6 −8
=> −x + 10 = 2x − 2
Transposing x to RHS and 2 to LHS, we get
=> 10 + 2 = 2x + x
=> 3x = 12
Dividing both sides by 3, we get
=> 3x 3 = 123
=> x = 4
Verification:
Substituting x = 4 on both sides, we get
3(4) − 2(2(4)−5) = 2(4+3)−8
12−2 (8 − 5) = 14−8
12 − 6 = 6
6 = 6
LHS = RHS
Hence, verified.
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