Question

2. By how much does 8x3 - 6x2 + 9x - 10 exceed 4x3 + 2x2 + 7x-3​

Answer 1

Answer:

8x3 – 6x2 + 9x – 10 exceeds 4x3 + 2x2 + 7x – 3

= (8x3 – 6x2 + 9x – 10) – (4x3 + 2x2 + 7x – 3)

= 8x3 – 6x2 + 9x – 10 – 4x3 – 2x2 – 7x + 13

= 8x3 – 4x3 – 6x2 – 2x2 + 9x – 7x – 10 + 3

= 4x3 – 8x2 + 2x – 7

Step-by-step explanation:

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