Question

2. By taking a right triangle ABC right angled at B in which ZA= 45°, calculate the values of sin 45°, cos 45º and tan 45º. 3​

Answer 1

Answer:

(i)

AC

BC

=sin45

∘

3

2

BC

=

2

1

Or BC=3

(ii) By Pythagoras theorem

(AB)

2

=(AC)

2

−(BC)

2

=(3

2

)

2

−(3)

2

=18−9

=9

AB=3 cm.

solution

Step-by-step explanation:

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Answer 2

Answer:

sin 45°  = $1/\sqrt{2}$

cos 45º = $1/\sqrt{2}$

tan 45º = sin 45° / sin 45°

=> tan 45º = $1/\sqrt{2}$/$1/\sqrt{2}$

=> tan 45º = 1