Question

2
(c) Prove the identity
1-tane
1-cote
= tan²0.​

Answer 1

(1-tanA)square / (1 -COtA) square (1-tanA) square / [ (tan A-1)/ tan A)] square (1-tanA) square / [(tanA - 1)sq/ tan sq A] (1-tanA)sq/[(1-tanA) sq / tan sq A] Tan sq A

Step-by-step explanation:

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