Question

2. Calcium carbonate is decomposed on heating in the following reaction.
CaCO3→CaO + CO2
a) How many moles of calcium carbonate are involved in this reaction?
b) Calculate the gram molecular mass of calcium carbonate involved in the
reaction?
c)How many moles of CO2 are there in this equation?​

Answer 1

Answer:

Number of moles of CO

2

= Number of moles of CaCO

3

=

Molarmass

Mass

=

100

50

=

2

1

Answer 2

ANSWER;

Calcium carbonate is decomposed in the reaction as carbon dioxide and calcium oxide..

The reaction is as follows

CaCO3  =CaO+CO2

a.From the above reaction it is clear that only one mole of calcium carbonate is involved in the reaction.

b.The gram molecular weight of CaCO3 is {Ca=40,C=12, O3=48}

So the gram molecular weight of calcium carbonate is 100

c.Only one mole of CO2 is involved in the reaction..