Question

2: Calculate mass of 10 -3 moles of MgSO4​

Answer 1

Explanation:

given in written form.

Answer 2

Answer:

The mass of 10⁻³ moles of MgSO₄ is 0.12 gm.

Explanation:

What are moles?

Moles may be defined as the ratio of the weight of the compound present to its molecular weight.

Mathematically,

$Moles (n) = \frac{mass}{MW} = \frac{w}{W}$

where,
n = no. of moles of the compound
w = weight of the compound present
W = molecular weight of the compound

Calculation:

Given that,

n = 10⁻³ moles
w = x (let)
W = molecular mass of MgSO₄
   = 24 + 32 + (16 × 4)
   = 120 gm [molar mass of Mg = 24 amu; S = 32 amu; O = 16 amu]

∴ By the probelm,

$10^{-3} = \frac{x}{120} \\ \Rightarrow x = 120 \times 10^{-3} \\ \Rightarrow x = \frac{120}{1000} = 0.12 gm$

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