Question

2. Calculate the amount and compound interest interest being compounded half-yearly) on
a) 300 for 3 year at 10% p.a.
please answer fast fast... ​

Answer 1

Given :-

• Principal = Rs,300
• Time = 3 years
• Rate = 10%

To Find :-

• Amount and Compound Interest

Solution :-

★ Amount ★

${:} \longrightarrow \sf{\sf{Amount \: = \: Principal \: × \: \bigg(1\: + \: \dfrac{Rate}{100}\bigg)^{Time} }}$

${:} \longrightarrow \sf{\sf{Amount \: = \: 300\: × \: \bigg(1\: + \: \dfrac{10}{100}\bigg)^{3} }}$

${:} \longrightarrow \sf{\sf{Amount \: = \: 300\: × \: \bigg( \: \dfrac{110}{100}\bigg)^{3} }}$

${:} \longrightarrow \sf{\sf{Amount \: = \: 300\: × \: \bigg( \: \dfrac{110}{100}\bigg) \: \times \: \bigg( \: \dfrac{110}{100}\bigg) \: \times \bigg( \: \dfrac{110}{100}\bigg)}}$

${:} \longrightarrow \sf{\sf{Amount \: = \: 3 \cancel{00}\: × \: \ \: \dfrac{11 \cancel0}{1 \cancel{00}} \: \times \: \: \dfrac{11 \cancel0}{1 \cancel{00}} \: \times \: \dfrac{11 \cancel0}{10 \cancel0}}}$

${:} \longrightarrow \sf{\sf{Amount \: = \: \dfrac{3 \: \times \: 11 \: \times \: 11 \: \times \: 11}{10} }}$

${:} \longrightarrow \sf{\sf{Amount \: = \: \dfrac{3993}{10} }}$

${:} \longrightarrow \sf{\bf{Amount \: = \: Rs,399.3 }}$

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★ Compound Interest ★

$\longmapsto\sf{ Compound \: Interest \: = \: Amount \: - \: Principal }$

$\longmapsto\sf{ Compound \: Interest \: = \: 399.3 \: - \: 300 }$

$\longmapsto\bf{ Compound \: Interest \: = \: Rs, 99.3 }$

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$\therefore \: \tt \: Compound \: interest \: = \: Rs,99.3$

$\therefore \: \tt \: Amount \: = \: Rs,399.3$

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