Question

2. Calculate the de-Broglie
wavelength of an electron of
energy 250eV​

Answer 1

Answer:

Correct option is

A

1.23A

0

E =

2

1

mv

2

= 100 eV = 100 × 1.6 × 10

−19

J

v

2

=

m

2E

v = (

m

2E

)

1/2)

=

2mE

λ =

mv

h

=

2mE

h

metre

λ =

(2×9.1×10

−31

×100×1.6×10

−19

6.6×10

−34

1/2

=1.23 × 10

−10

m = 1.23A