Question

2. Calculate the energy for the n=3 (H-atom).
0 -13.6 ev
O -1.5 ev
0 -0.8 év
0 -1.4 ev
Required​

Answer 1

Energy in nth state is given by -

E = -13.6 (Z/n)^2 eV

(where z is atomic number and n is the number of orbit.)

--> Energy in n = 3

=> E = -13.6 × (1/3)^2

=> E = -13.6 / 9 = -1.5 eV

Hope this helps !