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Calculate the energy stored in a capacitor of 47uF, if the
voltage across it is 100V. (Apr. 2014)
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Answer:
2.5 × 10⁻² J
Explanation:
We have given :
Potential difference V = 100 V
Capacitor of 5 μ F
We are asked to find energy stored :
We know :
U = 1 / 2 C V²
Putting values here we get :
U = 1 / 2 × 5 × 10⁻⁶ × 100² J
= > U = 2.5 × 10⁻² J
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