Question

2. Calculate the horse-power of an engine
that lifts 10 litre of water from a depth of
50m in 30 min.
( Take g= 10m/s^2, density of water =
1000kg/m^3, b.p = 746W)
need quick thx ​

Answer 1

Horse power of engine is 3 × 10^(-03) H.P.

Explanation

Given that an engine lifts 10 litre of water from a depth of 50 m in 30 min. g = 10 m/s², density of water = 1000 kg/m³, b.p. = 746W

We have to find horse power of engine.

Solution

Here, we have volume of water = 10 litres.

→ Volume = 1/10² m³

→ Volume = 0.01 m³

Now we have, density of water = 1000 kg/m³

As we know that,

❐ Mass = Volume * Density

✎ Mass = 0.01 × 1000

✎ Mass = 10 kg

Now, time = 30 mins.

✎ Time = (30 * 60) s

✎ Time = 1800 s

Now we know,

❐ Power (P) = (m * g * s)/T

✎ P = (10 * 10 * 50)/1800

✎ P = 5000/1800

✎ P = 2.78 W

Now we have,

❐ 746 W = 1 Horse power (H.P.)

✎ 1 W = 1/746 H.P.

✎ 2.78 W = 2.78/746 H.P.

✎ 2.78 W = 3.73 × 10^(-03) H.P.

Therefore, horse power of engine = 3.73 × 10^(-03) H.P.