Question

2. Calculate the mass of 12.044 x 1023 molecules of aluminium chloride
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Answer 1

Answer:

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Explanation:

1 mole of AlCl3 = 27 + 3×35.5 = 133.5

1 mole = 6.023 × 10^23 molecules

Therefore 12.044 × 10^23 molecules is 2 moles

Therefore mass of 12.044 x 1023 molecules of aluminium chloride is 2×133.5 = 267