2. Calculate the percentage loss of mass of hydrated copper[II] sulphate[CuSO4.5H20]
when it is completely dehydrated. [CuSO4.5H20 → CuSO4 + 5H20]
[At. wts. are Cu = 64, S = 32, O = 16, H = 1].
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Cu=64
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I think soo......
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