2.calculate the pH of a solution obtained by dissolving 0.02 mole of hydrochloric acid into 2 litre of the solution.
3.calculate the pH of a solution obtained obtained by dissolving 0.02 mole of sulfuric acid in 3 litres of the solution.
4. Calculate the pH of 10 raise to power minus 6 M NaOH solution.
5. A solution has pH = 3 it is diluted 1000 times what is the pH of the solution after dilution?
Answers
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Explanation:
Explanation:
In reverse order we may find the concentration of
H
C
l
(
a
q
)
by taking the quotient...
Concentration
=
Moles of solute
Volume of solution
=
0.02
⋅
m
o
l
2.0
⋅
L
[
H
C
l
]
=
0.010
⋅
m
o
l
−
1
=
1.0
×
10
−
2
⋅
m
o
l
⋅
L
−
1
...
But
p
H
=
−
log
10
[
H
3
O
+
]
=
−
log
10
(
10
−
2
)
=
−
−
2
=
+
2
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