Question

2. Calculate the resistance of 50cm length of wire of area 0.01mm ^2
and resistivity of 5x10^-8ohmm.​

Answer 1

Answer:-

we are given, length of wire,

$= l = 50 \: cm = 50 \times {10}^{ - 2} m$

Cross-sectional,

$= A = 0.01 { \: mm}^{2} = 0.01 \times {10}^{ - 6} {m}^{2}$

Resistivity,

$⇒ρ = 5 \times {10}^{ - 8} Ωm$

As resistance,

$⇒R = ρ \frac{l}{ A}$

$∴ \: R = \left( \frac{5 \times {10}^{ - 8} \times 50 \times {10}^{ - 2} }{0.01 \times {10}^{ - 6} } \right) \]Ω = 2.5Ω$

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