Question

2. Calculate the resonance energy of N O from the following
data: A Hºof N.0 = 82 KJ mol-
Bond energy of N=N. N=N, O=0 and N=O bonds
946, 418, 498 and 607 KJ mol-' respectively.​

Answer 1

Answer:

the equation from the formation ofone molecule of N2O will be

NEN (g) + 1/2 0=0 (g)---->N=N=0

calculate value of triangle fh0 =[B.E.(NEN)=1/2B.E.(0=0)]-[B.E.(N=N)=B.E.(N=0)]

=[946=1/2(498)]-[418=607] kj mol-1

resonance energy = observed  triangle fh0 - calculated  triangle fh0=82=170=-88kg mol-1

Explanation:

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Answer 2

Answer:

Heya

Explanation:

The equation for the formation of one mole of N2O will be  

NΞN (g) + ½ O=O (g) ---> N=N=O

Calculated value of ΔfH0 for this reaction will be ΔfH0 = [B.E.(NΞN) + ½ B.E.(O=O)] – [B.E.(N=N) + B.E.(N=O)]  

=[946 + ½ (498)] – [418 + 607] kj mol-1

= 170kj mol-1

Resonance energy = Observed ΔfH0 – Calculated ΔfH0

= 82 – 170 = - 88 kj mol-1

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