Question

2. Calculate the shortest and longest wavelengths of Balmer series of hydrogen
atom. Given R=1.097 x 10 m
Mar 16]
Ans 364 nm, 656 mm​

Answer 1

Answer:

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Explanation:

Calculate the longest and shortest wavelength in the Balmer series of hydrogen atom. Given Rydberg constant =1.0987×107m-1.

1λ=R[122-1n22]

∴1λ=1.097×107[122-132]=1.097×107×536.

∴1λ=1.097×107[122-1∞2]=1.097×1074.

Answer 2

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