2 capacitance of 6f and 3f are connected in series find the effective capacitance
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Answer:
Let C1=3 μF,C2=6 μF
C1 and C2 are connected in series with potential difference V=900 V acros the combination
Thus for the series combination Charge on both capacitor is same
∴C
1
V
1
=C
2
V
2
=Q ...1
∴
V
2
V
1
=
C
1
C
2
=2 μC ...2
also V
1
+V
2
=900 V ...3
From 2 and 3
V
2
=300 V and V
1
=600 V
Therefore charge on each capacitor Q=300×6=600×3=1800 μC
When these capacitors are disconnected and reconnected in parallel the charge is distributed and the potential difference is same
∴
C
1
Q
1
=
C
2
Q
2
=V ...4
∴
Q
2
Q
1
=
C
2
C
1
=
2
1
...5
and Q
1
+Q
2
=Q=1800 μC ...6
From 5 and 6
Q
1
=600 μC and Q
2
=1200 μC
Therefore the potential difference across the combination is V=
3
600
=
6
1200
=200 V
Ans is 200 V
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