Question

2 capacitor of capacitance 3 microfarad and 6 micro farad are charged to a potential 12V each they are now connected to each other with the positive plate of one joined to the negative plate pf another the potential difference across each will be????

Answer 1

Answer:

8V and 4V respectively

Explanation:

Given the capacitance of two capacitors are 3uF and 6uF

Let potential on 3uF=xV

potential on 6uF=12-x

3x=6(12-x)

9x=72

x=8 on 3uF

12-8=4 on 6uF

Answer 2

Given:

2 capacitor of capacitance 3 microfarad and 6 micro farad are charged to a potential 12V each they are now connected to each other with the positive plate of one joined to the negative plate pf another  

To find:

The potential difference across each will be?

Solution:

From given, we have,

2 capacitor of capacitance 3 microfarad and 6 microfarad are charged to a potential 12V each.

C1 = 3 μ F

C2 = 6 μ F

V1 = V2 = 12 V

The potential difference across each is given by,

V = (C1V1 - C2V2) / (C1 + C2)

V = (6 × 12 - 3 × 12) / (6 + 3)

V = (72 - 36) / 9

V = 36/9

∴ V = 4 V

Therefore, the potential difference across each will be 4 V.