2 cars starts from the same point at the same time. the first car travels at a constant speed of 12 km/h while the second car travels at an initial speed of 6 km/h , which increases by 1 km/h every hour . what will be the distance travelled by the second car by the time it meets the first car ?
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hii mate!!
Distance travelled in 'n' hours is Sn.
In the series of AP
a=6 d=1
Let the cars meet at 'n' hours
Thus,
12n = Sn
12n= n/2(2a+(n-1)d)
24 = 2a+(n-1)d
24 = 2(6) + (n-1)1
24 = 12 + n - 1
n = 13 hours
hope it helps ☺☺☺
Distance travelled in 'n' hours is Sn.
In the series of AP
a=6 d=1
Let the cars meet at 'n' hours
Thus,
12n = Sn
12n= n/2(2a+(n-1)d)
24 = 2a+(n-1)d
24 = 2(6) + (n-1)1
24 = 12 + n - 1
n = 13 hours
hope it helps ☺☺☺
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