Question

2
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1
:
5
di
If a force of 1200 N is acting normally on a surface with area 10 cm", then
the pressure on it is
(a) 1.2 x 106 Pa
b) 15x10 Pa
(c
) 2,5 x 106 Pa
d) 3.6 x 10 Pa​

Answer 1

Answer:

1.2×10^6 pa

Explanation:

Given, F=1200N

A=10cm^2=0.001m^2

we know,

Thrust is the force acting normally to a surface

so thrust=1200N

P=Thrust/area

P=1200/0.001

1200000pa

=1.2×10^6pa