Question

2. Charge through a conductor is given as a function of
time t as q = 4t2 + 4 + 4 coulomb. At 2 sec what is
the current flowing
a) 12 A
b) 8A
c) 20A
d) 28A
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Answer 1

Explanation:

q=(4t/2)+4+4

t=2sec

I=q/t

I=[(4×2/2)+8]/2

I=8A

Answer 2

Given: Charge through a conductor is given as a function of time t as q= 4t^2 + 4t+4.

To find: Current flowing at t= 2s

Explanation: The charge through a conductor and current through it is given by the relationship:

dq = idt where dq is a small change jn in charge and dt is a small time interval.

Now, dq= i dt

=> dq/dt = i

=> i = dq/dt

Here, we need to differentiate charge with respect to time.

q = 4t^2 + 4t +4

=> dq/dt = 8t+4

=> i = 8t + 4

At t= 2s, i = 8* 2 +4

= 20 A

Therefore, the current flowing at t= 2 s through the conductor is 20 Ampere.