Question

2 charges 4*10*-9 C and -16*10*-9 C are separated by a distance 20cm in air. the position of neutral point from the small charge is ​

Answer 1

Solve it by yourself...I am attaching formula.

hope it helps..

Answer 2

Dear Student,

◆ Answer -

16 cm

● Explanation -

# Given -

q1 = 4×10^-9 C

q2 = 16×10^-9 C

d = 20 cm

# Solution -

Position of neutral point from the small charge is -

x = d.q2/(q1+q2)

x = 20 × 16×10^-9 / (4×10^-9 + 16×10^-9)

x = 16 cm

Position of neutral point from the small charge is 16 cm.

Thanks dear. Hope this is helpful to you...