2 charges a kept at a distance r apart have a force of 27N between them If they are moved so that the distance between them is 1/3rd of the original distance, what is the force between them now?
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Answer - As we know,
The force is air F
a
=
4πϵ
0
1
r
2
q
1
q
2
The force in water F
w
=
4πϵ
0
K
1
r
2
q
1
q
2
∴
F
a
F
w
=
K
1
Dielectric constant of water is 81, so the force in water reduces to
81/1
times
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