Question

2 charges - q and q are located at points A (0,0,-2) and B 0,0,2. How much work will be done in moving a test charge from point P (4,0,0) to Q(-5,0,0)

Answer 1

Answer:

Explanation:

Zero. It's because the system as a whole is a dipole. So while moving a test charge perpendicular to the dipole, the work done becomes zero. It is explained by the formula U=kpcosx/(r²-a²cosx). Where x is the angle between dipole moment and the position vector of the test charge.