2. Check in which case the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial :
i) x²+3x+1,3x⁴+5x³-7x²+2x+2
Answers
Answer:
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Solution :-
Dividing second polynomial by the first polynomial we get,
x² + 3x + 1 ) 3x⁴ + 5x³ - 7x² + 2x + 2 ( 3x² - 4x + 2
3x⁴ + 9x³ + 3x²
- 4x³ - 10x² + 2x
- 4x³ - 12x² - 4x
2x² + 6x + 2
2x² + 6x + 2
0
we get,
→ Remainder = 0
→ Quotient = 3x² - 4x + 2 .
since we get remainder as 0, we can conclude that, the first polynomial is a factor of the second polynomial .
Learn more :-
JEE mains Question :-
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. Find all the zeroes of the polynomial x4
– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.
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