Question

2. Check whether the first polynomial is a factor of the second polynomial by dividing the
second polynomial by the first polynomial:
(1) t - 3,24 +3ť – 2t - 9t-12
(ii) x2 + 3x + 1, 3x4 + 5x3 – 7x2 + 2x + 2
(i) x2 – 3x + 1, x - 4x3 + x2 + 3x + 1
5​

Answer 1

Answer:

(i) t 2 −3,2t 4 +3t 3 −2t 2 −9t−12

Remainder is 0, hence t 2

−3 is a factor of 2t 4 +3t 3 −2t 2 −9t−12

(ii) x 2 +3x+1,3x 4 +5x 3 −7x 2 +2x+2

Remainder is 0, hence x 2 +3x+1 is a factor of 3x

4 +5x 3 −7x 2 +2x+2

(iii) x −3x+1,x 5 −4x 3 +x 2 +3x+1

Remainder is 2, hence x

3 −3x+1 is not a factor of x

5 −4x 3 +x 2 +3x+1

Step-by-step explanation:

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