2) Check whether the numbers . √2,√8, √18, √32. .......... are in A. P.? If it is
an A. P. then find s40
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√2,√8, √18, √32
d = √8 - √2
=> d = 2√2 - √2
=> d = √2
d = √18 - √8
=> d = 3√2 - 2√2
=> d = √2
d = √32 - √18
=> d = 4√2 - 3√2
=> d = √2
Since, the difference (d) is same
So, 2,√8, √18, √32 .......... are in A. P
Here, d = √2 ; a = √2
S40 = n/2 [2a + (n-1) d]
=> 40/2 [2(√2) + (40-1) √2]
=> 20 [2√2 + 39√2]
=> 20 × 41√2
=> 820√2
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