Question

2. Check whether the value given in the brackets is a solution to the given equation
or not:
(a) n + 5 = 19 (n = 1)
(b) 7n + 5 = 19 (n=-2)
(c) In + 5 = 19 (n=2)
(d) 4p - 3 = 13 (p = 1)
(e) 4p - 3 = 13 (p = -4) (1) 4p - 3 = 13 (p = 0)​

Answer 1

Answer:

see this is your answer

Step-by-step explanation:

(a) Put n = 1 in the equation, we have :

                          n  +  5  =  15

or                      1   + 5   = 15  

or                            6    \neq   15

Thus n = 1 is not a solution.

 

(b) Put  n  =  - 2, we have :

                         7n + 5 = 19

or                   7(-2)  + 5  =  - 14 + 5 = - 9  \neq 19.

So, n = - 2 is not a solution to given equation.  

 

(c) Put  n  =  2, we have :

                         7n + 5 = 19

or                   7(2)  + 5  = 14 + 5 = 19  = R.H.S

Thus n = 2 is the solution for the given equation.

 

(d) Put p = 1 , we have :

                         4p - 3  =  13

or                    4(1)  -  3   =  1   \neq   13 .

Thus p = 1 is not a solution.

 

(e)   Put p = - 4 , we get :

                      4p - 3  =  13

or                    4(1)  -  3   =  1   \neq   13 .

Thus p = 1 is not a solution.

 

(f)   Put p = 0 , we get :

                      4p - 3  =  13

or                    4(0)  -  3   =  - 3   \neq   13 .

Thus p = 0 is not a solution.