2 circles cut the point A and B. QS is the line drawn through B prove that angle APQ and angle ARS = 180°
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Join AB and let XY be the tangent at P. Then by alternate segment theorem,
∠APX=∠ABP ……………(i)
Next, ABCD is a cyclic quadrilateral, therefore, by the theorem sum of the opposite angles of a quadrilateral is 180^{\circ}
∠ABD+∠ACD=180
Also, ∠ABD=∠ABP=180
(Linear Pair)
∴∠ACD=∠ABP ...........(ii)
From (i) and (ii),
∠ACD=∠APX
∴XY∥CD (Since alternate angles are equal).
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