Question

2.
class mark of a particular class is 6.5 and the class size is 3.Then class interval is ​

Answer 1

$\huge{\bold{\sf{Given:}}}$

• $\small\sf{Class\: size\: of \:the \:class \:interval\: =\:3}$
• $\small\sf{Class \:mark\:=\:6.5}$

$\huge{\bold{\sf{Find:}}}$

• $\small\sf{Class\: Interval \:= \:?}$

$\huge{\bold{\sf{Solution:}}}$

$\small\sf{Let\: the \:a \:be\: the \:lower\: limit }$$\small\sf{of \:the \:class \:interval}$

• $\small\sf{∴ \:Upper\: limit\: of\: the\: class \:interval\:=\:a}$$\small\sf{+\:3}$

$\small\sf{\bold{Let's\:Start}}$

$\small\sf{∴}\:\small\sf\frac{a\:+\:a\:+\:3}{2}\:=\:6.5$

$\small\sf{\::⟹\:2a\:+\:3\:=\:6,5\:×\:2}$

$\small\sf{\::⟹\:2a\:=\:13\:−\:3}$

$\small\sf{\::⟹\:2a\:=\:10\:⟹\:a\:=}\:\small\sf\frac{\cancel{10}^{\:5}}{\cancel{2}}\:=\:5$

$\sf\small{∴\:a\:+\:3\:=\:5\:+\:3\:=\:8}$

• $\small{\bold{\underline{\underline{\boxed{\sf{Hence \:class \:interval\:=\: 5\:−\:8}}}}}}$

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