2 cloro hexane +Cl2+hv. ―> x
x =total number of di-chloro product
Answers
Answer:
Cl
H
3
C−
∣
C
∣
−CH
2
−CH
2
−CH
2
−CH
3
Cl
2
hν
(x)
H
The possible product may be
Cl
(1)H
2
∣
C
−
∣
C
∗
∣
−CH
2
−CH
2
−CH
2
−CH
3
⟶2
1
=2 stereoisomers
Cl H
Cl
(2) H
3
C−
∣
C
∣
−CH
2
−CH
2
−CH
2
−CH
3
⟶2
o
=1 stereoisomer
Cl
Cl Cl
(3) H
3
C−
∗
∣
C
∣
−
∗
∣
C
∣
−CH
2
−CH
2
−CH
3
=2
2
=4 stereoisomers
H H
Cl Cl
(4) H
3
C−
∗
∣
C
∣
−CH
2
−
∣
C
∗
∣
−CH
2
−CH
3
=2
2
=4 stereoisomers
H H
Cl Cl
(5) H
3
C−
∗
∣
C
∣
−CH
2
−CH
2
−
∗
∣
C
∣
−CH
3
= as it is symmetrical molecule= 2
2−1
+2
2/2−1
=3 stereoisomers
H H
Cl
(6) H
3
C−
∣
C
∣
−CH
2
−CH
2
−CH
2
−CH
2
−Cl=2
1
=2 stereoisomers
H