Question

2 cm tall
object is placed perpendicular to the principal axis of a concave mirror of focal length 10cm the distance of the object from the mirror is 15 cm find the position size and the nature of the image formed

Answer 1

U(Object distance)= -15 cm

F(Focal Length, Concave Mirror is negative) = -10 cm

Using Mirror Formula,

1/F = 1/U + 1/V

1/-10 = 1/-15 +1/V

-1/10 = -1/15 +1/V

1/15 - 1/10 = 1/V

(2-3)/30 = 1/V

-1/30 = 1/V

V = -30

Magnification = -V/U ( - Image Distance / Object Distance)

Magnification = -(-30)/-15

M= 30/-15

M = -2

So the nature of the image will be Real and Inverted, position of the Image would be -30 cm, Size of the image would be twice the object (enlarged).

Please verify all the calculations first, because I am not good at calculations at all.

If you find my answer to be correct and helpful, please mark my answer as BRAINLIEST.

THANKS...

Answer 2

U(Object distance)= -15 cm

F(Focal Length, Concave Mirror is negative) = -10 cm

Using Mirror Formula,

1/F = 1/U + 1/V

1/-10 = 1/-15 +1/V

-1/10 = -1/15 +1/V

1/15 - 1/10 = 1/V

(2-3)/30 = 1/V

-1/30 = 1/V

V = -30

Magnification = -V/U ( - Image Distance / Object Distance)

Magnification = -(-30)/-15

M= 30/-15

M = -2

So the nature of the image will be Real and Inverted, position of the Image would be -30 cm, Size of the image would be twice the object (enlarged).