2 cm tall
object is placed perpendicular to the principal axis of a concave mirror of focal length 10cm the distance of the object from the mirror is 15 cm find the position size and the nature of the image formed
Answers
U(Object distance)= -15 cm
F(Focal Length, Concave Mirror is negative) = -10 cm
Using Mirror Formula,
1/F = 1/U + 1/V
1/-10 = 1/-15 +1/V
-1/10 = -1/15 +1/V
1/15 - 1/10 = 1/V
(2-3)/30 = 1/V
-1/30 = 1/V
V = -30
Magnification = -V/U ( - Image Distance / Object Distance)
Magnification = -(-30)/-15
M= 30/-15
M = -2
So the nature of the image will be Real and Inverted, position of the Image would be -30 cm, Size of the image would be twice the object (enlarged).
Please verify all the calculations first, because I am not good at calculations at all.
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THANKS...
U(Object distance)= -15 cm
F(Focal Length, Concave Mirror is negative) = -10 cm
Using Mirror Formula,
1/F = 1/U + 1/V
1/-10 = 1/-15 +1/V
-1/10 = -1/15 +1/V
1/15 - 1/10 = 1/V
(2-3)/30 = 1/V
-1/30 = 1/V
V = -30
Magnification = -V/U ( - Image Distance / Object Distance)
Magnification = -(-30)/-15
M= 30/-15
M = -2
So the nature of the image will be Real and Inverted, position of the Image would be -30 cm, Size of the image would be twice the object (enlarged).