Question

2 coins are tossed at once, find the probability of getting atleast 2 heads​

Answer 1

Answer:

(i) Let E1 = event of getting 2 heads. Then, E1={HH} and, therefore, n(E1)=1. ∴ P (getting 2 heads) =P(E1)=n(E1)n(S)=14

Step-by-step explanation:

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Answer 2

Answer:

(i) Let E1 = event of getting 2 heads. Then, E1={HH} and, therefore, n(E1)=1. ∴ P (getting 2 heads) =P(E1)=n(E1)n(S)=14