2 coins are tossed simultaneously find the probability of getting (a) atleast 1 head (b) a tail
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Step-by-step explanation:
When two coins are tossed the results are (HH,HT,TH,TT)
Total no. of outcomes =4
1) Exactly one head = only two cases are (HT,TH)
=42=21
2) At least one tail = There are three cases (HT,TH,TT)
=43
3) No. tail = only one case (HH) =41
4) Atmost one head =three cases (HT,TH,TT)
=43.
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Answer:
Step-by-step explanation:
there are in total four possibilities HH,TH,HT,TT
a) atleast one head means hh,th,ht so 3
hence 3/4
b)a tail means th ,ht so 2
hence 2/4= 1/2
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