Math, asked by rittikaroy22, 9 hours ago

2 coins are tossed simultaneously find the probability of getting (a) atleast 1 head (b) a tail

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Answers

Answered by SuryaDevil1290
0

Step-by-step explanation:

When two coins are tossed the results are (HH,HT,TH,TT)

Total no. of outcomes =4

1) Exactly one head = only two cases are (HT,TH)

=42=21

2) At least one tail = There are three cases (HT,TH,TT)

=43

3) No. tail = only one case (HH) =41

4) Atmost one head =three cases (HT,TH,TT)

=43.

Answered by GauthmathMagnus
0

Answer:

Step-by-step explanation:

there are in total four possibilities HH,TH,HT,TT

a) atleast one head means hh,th,ht so 3

hence 3/4

b)a tail means th ,ht so 2

hence 2/4= 1/2

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