Question

2 coins are tossed simultaneously, Find the probability of getting at-least 1 head and 1 tail​

Answer 1

Step-by-step explanation:

Let H be heads and T be tails

All the possibilities when the 2 coins are tossed -

(H,H) , (H,T) , (T,T) , (T,H)

Now, probability (getting atleast 1head and 1tail)

= 2/4 = 1/2

Answer 2

Here H is denoted for head and T is denoted for tail.

When two different coins are tossed randomly, the sample space is given by S = {HH, HT, TH, TT}

Therefore, n(S) = 4.

getting 1 head and 1 tail:

Let E9 = event of getting 1 head and 1 tail.

Then,

E9 = {HT, TH } and, therefore, n(E9) = 2.

Therefore,

P(getting 1 head and 1 tail) = P(E9)

= n(E9)/n(S) = 2/4

= 1/2.