Math, asked by poondekdee2009, 7 months ago

2.Comment on the nature of roots for 4x^2-5=2(〖x+1)〗^2-7 plz, help...

Answers

Answered by natasha149025

1

Answer:

4x^2 - 5=2(x^2 +2x+1)-7=0

4x^2 - 5=2x^2 +4x+2-7=0

2x^2 - 4x=0

2x(x-2)=0

x=0, x=2

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