2 complementary angles are in such a way that twice one angle is thrice the other angle
ashishkhare687:
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Answered by
6
let the angles be x and y
complementary angles add up to give 90°
thus
2x=3y,x=3y/2 - letthis be equation 1
x+y=90
3y/2+y=90 (by equation 1)
5y/2=90
5y=180
y=36
thus, x=54
complementary angles add up to give 90°
thus
2x=3y,x=3y/2 - letthis be equation 1
x+y=90
3y/2+y=90 (by equation 1)
5y/2=90
5y=180
y=36
thus, x=54
Answered by
6
let first angle is x and second be y
sum of complementary angles
x + y = 90..................(i)
ATQ
2x = 3y
x=3y/2
Put x in eq (i)
x + y = 90
3y/2 +y = 90
Now take LCM
(3y+2y)/2 = 90
5y = 180
y=180/5
y = 36
put y in (i)
x + y = 90
x + 36 = 90
x = 90 - 36
x = 54
FIRST ANGLE =54
SECOND ANGLE = 36
sum of complementary angles
x + y = 90..................(i)
ATQ
2x = 3y
x=3y/2
Put x in eq (i)
x + y = 90
3y/2 +y = 90
Now take LCM
(3y+2y)/2 = 90
5y = 180
y=180/5
y = 36
put y in (i)
x + y = 90
x + 36 = 90
x = 90 - 36
x = 54
FIRST ANGLE =54
SECOND ANGLE = 36
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