Math, asked by sindrela38, 12 days ago

2) complete the following activity to find the sum of natural numbers between 1 and 140.
Which are divisible by 4.
The numbers between 1 and 140 divisible by 4 are 4,8,12 ,....,136.
Here, a=4 ,d=4, tn= 136.
tn=a+(n-1)d. (Formula)
136= + (n-1) x4
n= []
Sn=(n/2)x [] (formula)
S34=(34/2)(8+(34-1)x4]
S34= 1)​

Answers

Answered by yadhukrishna9
0
Bababababbaababbabaabababbabba
Answered by patangraobhumi
0

tn=a+(n-1) d____ by formula

136=4+(n-1) 4

n=34

sn=n/2(2a+(n-1) d)

s34=34/2(8+(34-1)x4)

s34=2389

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